4(2n+1)=(6n+3)+1

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Solution for 4(2n+1)=(6n+3)+1 equation: 



4(2n+1)=(6n+3)+1

We move all terms to the left:

4(2n+1)-((6n+3)+1)=0

We multiply parentheses

8n-((6n+3)+1)+4=0



We calculate terms in parentheses: -((6n+3)+1), so:

(6n+3)+1

We get rid of parentheses

6n+3+1

We add all the numbers together, and all the variables

6n+4

Back to the equation:

-(6n+4)



We get rid of parentheses

8n-6n-4+4=0

We add all the numbers together, and all the variables

2n=0

n=0/2

n=0

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