4(2n+1)=(6n+3)+1

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Solution for 4(2n+1)=(6n+3)+1 equation:



4(2n+1)=(6n+3)+1
We move all terms to the left:
4(2n+1)-((6n+3)+1)=0
We multiply parentheses
8n-((6n+3)+1)+4=0
We calculate terms in parentheses: -((6n+3)+1), so:
(6n+3)+1
We get rid of parentheses
6n+3+1
We add all the numbers together, and all the variables
6n+4
Back to the equation:
-(6n+4)
We get rid of parentheses
8n-6n-4+4=0
We add all the numbers together, and all the variables
2n=0
n=0/2
n=0

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