4(2n+2)=4(n+1)+3n

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Solution for 4(2n+2)=4(n+1)+3n equation:



4(2n+2)=4(n+1)+3n
We move all terms to the left:
4(2n+2)-(4(n+1)+3n)=0
We multiply parentheses
8n-(4(n+1)+3n)+8=0
We calculate terms in parentheses: -(4(n+1)+3n), so:
4(n+1)+3n
We add all the numbers together, and all the variables
3n+4(n+1)
We multiply parentheses
3n+4n+4
We add all the numbers together, and all the variables
7n+4
Back to the equation:
-(7n+4)
We get rid of parentheses
8n-7n-4+8=0
We add all the numbers together, and all the variables
n+4=0
We move all terms containing n to the left, all other terms to the right
n=-4

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