4(2n+3)-3(n-1)=-3

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Solution for 4(2n+3)-3(n-1)=-3 equation:



4(2n+3)-3(n-1)=-3
We move all terms to the left:
4(2n+3)-3(n-1)-(-3)=0
We add all the numbers together, and all the variables
4(2n+3)-3(n-1)+3=0
We multiply parentheses
8n-3n+12+3+3=0
We add all the numbers together, and all the variables
5n+18=0
We move all terms containing n to the left, all other terms to the right
5n=-18
n=-18/5
n=-3+3/5

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