4(2n+3)-3(n-1)=-3

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Solution for 4(2n+3)-3(n-1)=-3 equation: 



4(2n+3)-3(n-1)=-3

We move all terms to the left:

4(2n+3)-3(n-1)-(-3)=0

We add all the numbers together, and all the variables

4(2n+3)-3(n-1)+3=0

We multiply parentheses

8n-3n+12+3+3=0

We add all the numbers together, and all the variables

5n+18=0

We move all terms containing n to the left, all other terms to the right

5n=-18

n=-18/5

n=-3+3/5

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