4(2n+3)=8(9n+5)+7

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Solution for 4(2n+3)=8(9n+5)+7 equation: 



4(2n+3)=8(9n+5)+7

We move all terms to the left:

4(2n+3)-(8(9n+5)+7)=0

We multiply parentheses

8n-(8(9n+5)+7)+12=0



We calculate terms in parentheses: -(8(9n+5)+7), so:

8(9n+5)+7

We multiply parentheses

72n+40+7

We add all the numbers together, and all the variables

72n+47

Back to the equation:

-(72n+47)



We get rid of parentheses

8n-72n-47+12=0

We add all the numbers together, and all the variables

-64n-35=0

We move all terms containing n to the left, all other terms to the right

-64n=35

n=35/-64

n=-35/64

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