4(2n+35)+7(n+1)=

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Solution for 4(2n+35)+7(n+1)= equation:


Simplifying
4(2n + 35) + 7(n + 1) = 0

Reorder the terms:
4(35 + 2n) + 7(n + 1) = 0
(35 * 4 + 2n * 4) + 7(n + 1) = 0
(140 + 8n) + 7(n + 1) = 0

Reorder the terms:
140 + 8n + 7(1 + n) = 0
140 + 8n + (1 * 7 + n * 7) = 0
140 + 8n + (7 + 7n) = 0

Reorder the terms:
140 + 7 + 8n + 7n = 0

Combine like terms: 140 + 7 = 147
147 + 8n + 7n = 0

Combine like terms: 8n + 7n = 15n
147 + 15n = 0

Solving
147 + 15n = 0

Solving for variable 'n'.

Move all terms containing n to the left, all other terms to the right.

Add '-147' to each side of the equation.
147 + -147 + 15n = 0 + -147

Combine like terms: 147 + -147 = 0
0 + 15n = 0 + -147
15n = 0 + -147

Combine like terms: 0 + -147 = -147
15n = -147

Divide each side by '15'.
n = -9.8

Simplifying
n = -9.8

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