4(2n+4)4=4(n-1)-20

Solution for 4(2n+4)4=4(n-1)-20 equation:

4(2n+4)4=4(n-1)-20

We move all terms to the left:

4(2n+4)4-(4(n-1)-20)=0

We multiply parentheses

32n-(4(n-1)-20)+64=0


We calculate terms in parentheses: -(4(n-1)-20), so:

4(n-1)-20

We multiply parentheses

4n-4-20

We add all the numbers together, and all the variables

4n-24

Back to the equation:

-(4n-24)


We get rid of parentheses

32n-4n+24+64=0

We add all the numbers together, and all the variables

28n+88=0

We move all terms containing n to the left, all other terms to the right

28n=-88

n=-88/28

n=-3+1/7