4(2n+4)=7(3n+2)+4

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Solution for 4(2n+4)=7(3n+2)+4 equation: 



4(2n+4)=7(3n+2)+4

We move all terms to the left:

4(2n+4)-(7(3n+2)+4)=0

We multiply parentheses

8n-(7(3n+2)+4)+16=0



We calculate terms in parentheses: -(7(3n+2)+4), so:

7(3n+2)+4

We multiply parentheses

21n+14+4

We add all the numbers together, and all the variables

21n+18

Back to the equation:

-(21n+18)



We get rid of parentheses

8n-21n-18+16=0

We add all the numbers together, and all the variables

-13n-2=0

We move all terms containing n to the left, all other terms to the right

-13n=2

n=2/-13

n=-2/13

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