4(2n+4)=7(4n+2)+8

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Solution for 4(2n+4)=7(4n+2)+8 equation: 



4(2n+4)=7(4n+2)+8

We move all terms to the left:

4(2n+4)-(7(4n+2)+8)=0

We multiply parentheses

8n-(7(4n+2)+8)+16=0



We calculate terms in parentheses: -(7(4n+2)+8), so:

7(4n+2)+8

We multiply parentheses

28n+14+8

We add all the numbers together, and all the variables

28n+22

Back to the equation:

-(28n+22)



We get rid of parentheses

8n-28n-22+16=0

We add all the numbers together, and all the variables

-20n-6=0

We move all terms containing n to the left, all other terms to the right

-20n=6

n=6/-20

n=-3/10

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