4(2n+4)=7(9n+2)+6

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Solution for 4(2n+4)=7(9n+2)+6 equation: 



4(2n+4)=7(9n+2)+6

We move all terms to the left:

4(2n+4)-(7(9n+2)+6)=0

We multiply parentheses

8n-(7(9n+2)+6)+16=0



We calculate terms in parentheses: -(7(9n+2)+6), so:

7(9n+2)+6

We multiply parentheses

63n+14+6

We add all the numbers together, and all the variables

63n+20

Back to the equation:

-(63n+20)



We get rid of parentheses

8n-63n-20+16=0

We add all the numbers together, and all the variables

-55n-4=0

We move all terms containing n to the left, all other terms to the right

-55n=4

n=4/-55

n=-4/55

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