4(2n+5)-n=3n-2(1-2n)

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Solution for 4(2n+5)-n=3n-2(1-2n) equation: 



4(2n+5)-n=3n-2(1-2n)

We move all terms to the left:

4(2n+5)-n-(3n-2(1-2n))=0

We add all the numbers together, and all the variables

4(2n+5)-n-(3n-2(-2n+1))=0

We add all the numbers together, and all the variables

-1n+4(2n+5)-(3n-2(-2n+1))=0

We multiply parentheses

-1n+8n-(3n-2(-2n+1))+20=0



We calculate terms in parentheses: -(3n-2(-2n+1)), so:

3n-2(-2n+1)

We multiply parentheses

3n+4n-2

We add all the numbers together, and all the variables

7n-2

Back to the equation:

-(7n-2)



We add all the numbers together, and all the variables

7n-(7n-2)+20=0

We get rid of parentheses

7n-7n+2+20=0

We add all the numbers together, and all the variables

22!=0

There is no solution for this equation

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