4(2n-1)=3(n-3)+2(n+1)

Solution for 4(2n-1)=3(n-3)+2(n+1) equation:

4(2n-1)=3(n-3)+2(n+1)

We move all terms to the left:

4(2n-1)-(3(n-3)+2(n+1))=0

We multiply parentheses

8n-(3(n-3)+2(n+1))-4=0


We calculate terms in parentheses: -(3(n-3)+2(n+1)), so:

3(n-3)+2(n+1)

We multiply parentheses

3n+2n-9+2

We add all the numbers together, and all the variables

5n-7

Back to the equation:

-(5n-7)


We get rid of parentheses

8n-5n+7-4=0

We add all the numbers together, and all the variables

3n+3=0

We move all terms containing n to the left, all other terms to the right

3n=-3

n=-3/3

n=-1