4(2n-5)+2(3n-4)=6

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Solution for 4(2n-5)+2(3n-4)=6 equation: 



4(2n-5)+2(3n-4)=6

We move all terms to the left:

4(2n-5)+2(3n-4)-(6)=0

We multiply parentheses

8n+6n-20-8-6=0

We add all the numbers together, and all the variables

14n-34=0

We move all terms containing n to the left, all other terms to the right

14n=34

n=34/14

n=2+3/7

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