4(2n-6)+4n=72

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Solution for 4(2n-6)+4n=72 equation: 



4(2n-6)+4n=72

We move all terms to the left:

4(2n-6)+4n-(72)=0

We add all the numbers together, and all the variables

4n+4(2n-6)-72=0

We multiply parentheses

4n+8n-24-72=0

We add all the numbers together, and all the variables

12n-96=0

We move all terms containing n to the left, all other terms to the right

12n=96

n=96/12

n=8

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