4(2p+1)=27+3(2p-5)

Solution for 4(2p+1)=27+3(2p-5) equation:

4(2p+1)=27+3(2p-5)

We move all terms to the left:

4(2p+1)-(27+3(2p-5))=0

We multiply parentheses

8p-(27+3(2p-5))+4=0


We calculate terms in parentheses: -(27+3(2p-5)), so:

27+3(2p-5)

determiningTheFunctionDomain
3(2p-5)+27

We multiply parentheses

6p-15+27

We add all the numbers together, and all the variables

6p+12

Back to the equation:

-(6p+12)


We get rid of parentheses

8p-6p-12+4=0

We add all the numbers together, and all the variables

2p-8=0

We move all terms containing p to the left, all other terms to the right

2p=8

p=8/2

p=4