4(2q-2)+4=5-2(q+2)

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Solution for 4(2q-2)+4=5-2(q+2) equation: 



4(2q-2)+4=5-2(q+2)

We move all terms to the left:

4(2q-2)+4-(5-2(q+2))=0

We multiply parentheses

8q-(5-2(q+2))-8+4=0



We calculate terms in parentheses: -(5-2(q+2)), so:

5-2(q+2)

determiningTheFunctionDomain
-2(q+2)+5

We multiply parentheses

-2q-4+5

We add all the numbers together, and all the variables

-2q+1

Back to the equation:

-(-2q+1)



We add all the numbers together, and all the variables

8q-(-2q+1)-4=0

We get rid of parentheses

8q+2q-1-4=0

We add all the numbers together, and all the variables

10q-5=0

We move all terms containing q to the left, all other terms to the right

10q=5

q=5/10

q=1/2

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