4(2q-5)=-7(5q-1)

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Solution for 4(2q-5)=-7(5q-1) equation: 



4(2q-5)=-7(5q-1)

We move all terms to the left:

4(2q-5)-(-7(5q-1))=0

We multiply parentheses

8q-(-7(5q-1))-20=0



We calculate terms in parentheses: -(-7(5q-1)), so:

-7(5q-1)

We multiply parentheses

-35q+7

Back to the equation:

-(-35q+7)



We get rid of parentheses

8q+35q-7-20=0

We add all the numbers together, and all the variables

43q-27=0

We move all terms containing q to the left, all other terms to the right

43q=27

q=27/43

q=27/43

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