4(2r+1)-3(2r-5)=40

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Solution for 4(2r+1)-3(2r-5)=40 equation: 


Simplifying
4(2r + 1) + -3(2r + -5) = 40

Reorder the terms:
4(1 + 2r) + -3(2r + -5) = 40
(1 * 4 + 2r * 4) + -3(2r + -5) = 40
(4 + 8r) + -3(2r + -5) = 40

Reorder the terms:
4 + 8r + -3(-5 + 2r) = 40
4 + 8r + (-5 * -3 + 2r * -3) = 40
4 + 8r + (15 + -6r) = 40

Reorder the terms:
4 + 15 + 8r + -6r = 40

Combine like terms: 4 + 15 = 19
19 + 8r + -6r = 40

Combine like terms: 8r + -6r = 2r
19 + 2r = 40

Solving
19 + 2r = 40

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-19' to each side of the equation.
19 + -19 + 2r = 40 + -19

Combine like terms: 19 + -19 = 0
0 + 2r = 40 + -19
2r = 40 + -19

Combine like terms: 40 + -19 = 21
2r = 21

Divide each side by '2'.
r = 10.5

Simplifying
r = 10.5

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