4(2r+1)-3(r-5)=29

Solution for 4(2r+1)-3(r-5)=29 equation:

Simplifying
4(2r + 1) + -3(r + -5) = 29

Reorder the terms:
4(1 + 2r) + -3(r + -5) = 29
(1 * 4 + 2r * 4) + -3(r + -5) = 29
(4 + 8r) + -3(r + -5) = 29

Reorder the terms:
4 + 8r + -3(-5 + r) = 29
4 + 8r + (-5 * -3 + r * -3) = 29
4 + 8r + (15 + -3r) = 29

Reorder the terms:
4 + 15 + 8r + -3r = 29

Combine like terms: 4 + 15 = 19
19 + 8r + -3r = 29

Combine like terms: 8r + -3r = 5r
19 + 5r = 29

Solving
19 + 5r = 29

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-19' to each side of the equation.
19 + -19 + 5r = 29 + -19

Combine like terms: 19 + -19 = 0
0 + 5r = 29 + -19
5r = 29 + -19

Combine like terms: 29 + -19 = 10
5r = 10

Divide each side by '5'.
r = 2

Simplifying
r = 2