4(2r+3)=15r-11

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Solution for 4(2r+3)=15r-11 equation: 



4(2r+3)=15r-11

We move all terms to the left:

4(2r+3)-(15r-11)=0

We multiply parentheses

8r-(15r-11)+12=0

We get rid of parentheses

8r-15r+11+12=0

We add all the numbers together, and all the variables

-7r+23=0

We move all terms containing r to the left, all other terms to the right

-7r=-23

r=-23/-7

r=3+2/7

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