4(2r+3)=15r-11+1=7r

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Solution for 4(2r+3)=15r-11+1=7r equation: 



4(2r+3)=15r-11+1=7r

We move all terms to the left:

4(2r+3)-(15r-11+1)=0

We add all the numbers together, and all the variables

4(2r+3)-(15r-10)=0

We multiply parentheses

8r-(15r-10)+12=0

We get rid of parentheses

8r-15r+10+12=0

We add all the numbers together, and all the variables

-7r+22=0

We move all terms containing r to the left, all other terms to the right

-7r=-22

r=-22/-7

r=3+1/7

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