4(2r-3)=-2(3r+16)

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Solution for 4(2r-3)=-2(3r+16) equation: 



4(2r-3)=-2(3r+16)

We move all terms to the left:

4(2r-3)-(-2(3r+16))=0

We multiply parentheses

8r-(-2(3r+16))-12=0



We calculate terms in parentheses: -(-2(3r+16)), so:

-2(3r+16)

We multiply parentheses

-6r-32

Back to the equation:

-(-6r-32)



We get rid of parentheses

8r+6r+32-12=0

We add all the numbers together, and all the variables

14r+20=0

We move all terms containing r to the left, all other terms to the right

14r=-20

r=-20/14

r=-1+3/7

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