4(2r-4)+32=

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Solution for 4(2r-4)+32= equation:


4(2r-4)+32=0

We simplify the equation to the form, which is simple to understand 
4(2r-4)+32=0

Reorder the terms in parentheses
+(+8r-16)+32=0

Remove unnecessary parentheses
+8r-16+32=0

We move all terms containing r to the left and all other terms to the right. 
+8r=0+16-32

We simplify left and right side of the equation. 
+8r=-16

We divide both sides of the equation by 8 to get r. 
r=-2

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