4(2r-8)=7(10+r)

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Solution for 4(2r-8)=7(10+r) equation: 



4(2r-8)=7(10+r)

We move all terms to the left:

4(2r-8)-(7(10+r))=0

We add all the numbers together, and all the variables

4(2r-8)-(7(r+10))=0

We multiply parentheses

8r-(7(r+10))-32=0



We calculate terms in parentheses: -(7(r+10)), so:

7(r+10)

We multiply parentheses

7r+70

Back to the equation:

-(7r+70)



We get rid of parentheses

8r-7r-70-32=0

We add all the numbers together, and all the variables

r-102=0

We move all terms containing r to the left, all other terms to the right

r=102

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