4(2s+3)=1

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Solution for 4(2s+3)=1 equation: 



4(2s+3)=1

We move all terms to the left:

4(2s+3)-(1)=0

We multiply parentheses

8s+12-1=0

We add all the numbers together, and all the variables

8s+11=0

We move all terms containing s to the left, all other terms to the right

8s=-11

s=-11/8

s=-1+3/8

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