4(2s+3r+1)=

Solution for 4(2s+3r+1)= equation:

Simplifying
4(2s + 3r + 1) = 0

Reorder the terms:
4(1 + 3r + 2s) = 0
(1 * 4 + 3r * 4 + 2s * 4) = 0
(4 + 12r + 8s) = 0

Solving
4 + 12r + 8s = 0

Solving for variable 'r'.

Move all terms containing r to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + 12r + -4 + 8s = 0 + -4

Reorder the terms:
4 + -4 + 12r + 8s = 0 + -4

Combine like terms: 4 + -4 = 0
0 + 12r + 8s = 0 + -4
12r + 8s = 0 + -4

Combine like terms: 0 + -4 = -4
12r + 8s = -4

Add '-8s' to each side of the equation.
12r + 8s + -8s = -4 + -8s

Combine like terms: 8s + -8s = 0
12r + 0 = -4 + -8s
12r = -4 + -8s

Divide each side by '12'.
r = -0.3333333333 + -0.6666666667s

Simplifying
r = -0.3333333333 + -0.6666666667s