4(2s-3)=4(s+1)

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Solution for 4(2s-3)=4(s+1) equation: 



4(2s-3)=4(s+1)

We move all terms to the left:

4(2s-3)-(4(s+1))=0

We multiply parentheses

8s-(4(s+1))-12=0



We calculate terms in parentheses: -(4(s+1)), so:

4(s+1)

We multiply parentheses

4s+4

Back to the equation:

-(4s+4)



We get rid of parentheses

8s-4s-4-12=0

We add all the numbers together, and all the variables

4s-16=0

We move all terms containing s to the left, all other terms to the right

4s=16

s=16/4

s=4

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