4(2t+1)+t=(t+2)

Solution for 4(2t+1)+t=(t+2) equation:

4(2t+1)+t=(t+2)

We move all terms to the left:

4(2t+1)+t-((t+2))=0

We add all the numbers together, and all the variables

t+4(2t+1)-((t+2))=0

We multiply parentheses

t+8t-((t+2))+4=0


We calculate terms in parentheses: -((t+2)), so:

(t+2)

We get rid of parentheses

t+2

Back to the equation:

-(t+2)


We add all the numbers together, and all the variables

9t-(t+2)+4=0

We get rid of parentheses

9t-t-2+4=0

We add all the numbers together, and all the variables

8t+2=0

We move all terms containing t to the left, all other terms to the right

8t=-2

t=-2/8

t=-1/4