4(2t+1)-3(2t-5)=29

Solution for 4(2t+1)-3(2t-5)=29 equation:

Simplifying
4(2t + 1) + -3(2t + -5) = 29

Reorder the terms:
4(1 + 2t) + -3(2t + -5) = 29
(1 * 4 + 2t * 4) + -3(2t + -5) = 29
(4 + 8t) + -3(2t + -5) = 29

Reorder the terms:
4 + 8t + -3(-5 + 2t) = 29
4 + 8t + (-5 * -3 + 2t * -3) = 29
4 + 8t + (15 + -6t) = 29

Reorder the terms:
4 + 15 + 8t + -6t = 29

Combine like terms: 4 + 15 = 19
19 + 8t + -6t = 29

Combine like terms: 8t + -6t = 2t
19 + 2t = 29

Solving
19 + 2t = 29

Solving for variable 't'.

Move all terms containing t to the left, all other terms to the right.

Add '-19' to each side of the equation.
19 + -19 + 2t = 29 + -19

Combine like terms: 19 + -19 = 0
0 + 2t = 29 + -19
2t = 29 + -19

Combine like terms: 29 + -19 = 10
2t = 10

Divide each side by '2'.
t = 5

Simplifying
t = 5