4(2t+1)=2(7t+7)

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Solution for 4(2t+1)=2(7t+7) equation: 



4(2t+1)=2(7t+7)

We move all terms to the left:

4(2t+1)-(2(7t+7))=0

We multiply parentheses

8t-(2(7t+7))+4=0



We calculate terms in parentheses: -(2(7t+7)), so:

2(7t+7)

We multiply parentheses

14t+14

Back to the equation:

-(14t+14)



We get rid of parentheses

8t-14t-14+4=0

We add all the numbers together, and all the variables

-6t-10=0

We move all terms containing t to the left, all other terms to the right

-6t=10

t=10/-6

t=-1+2/3

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