4(2t+1)=64

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Solution for 4(2t+1)=64 equation: 



4(2t+1)=64

We move all terms to the left:

4(2t+1)-(64)=0

We multiply parentheses

8t+4-64=0

We add all the numbers together, and all the variables

8t-60=0

We move all terms containing t to the left, all other terms to the right

8t=60

t=60/8

t=7+1/2

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