4(2t+3)=2(7t+10)

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Solution for 4(2t+3)=2(7t+10) equation: 



4(2t+3)=2(7t+10)

We move all terms to the left:

4(2t+3)-(2(7t+10))=0

We multiply parentheses

8t-(2(7t+10))+12=0



We calculate terms in parentheses: -(2(7t+10)), so:

2(7t+10)

We multiply parentheses

14t+20

Back to the equation:

-(14t+20)



We get rid of parentheses

8t-14t-20+12=0

We add all the numbers together, and all the variables

-6t-8=0

We move all terms containing t to the left, all other terms to the right

-6t=8

t=8/-6

t=-1+1/3

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