4(2t+5)-21=7t+-6

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Solution for 4(2t+5)-21=7t+-6 equation: 



4(2t+5)-21=7t+-6

We move all terms to the left:

4(2t+5)-21-(7t+-6)=0

We add all the numbers together, and all the variables

4(2t+5)-(7t-6)-21=0

We multiply parentheses

8t-(7t-6)+20-21=0

We get rid of parentheses

8t-7t+6+20-21=0

We add all the numbers together, and all the variables

t+5=0

We move all terms containing t to the left, all other terms to the right

t=-5

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