4(2t+5)=2(1-4t)-22

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Solution for 4(2t+5)=2(1-4t)-22 equation: 



4(2t+5)=2(1-4t)-22

We move all terms to the left:

4(2t+5)-(2(1-4t)-22)=0

We add all the numbers together, and all the variables

4(2t+5)-(2(-4t+1)-22)=0

We multiply parentheses

8t-(2(-4t+1)-22)+20=0



We calculate terms in parentheses: -(2(-4t+1)-22), so:

2(-4t+1)-22

We multiply parentheses

-8t+2-22

We add all the numbers together, and all the variables

-8t-20

Back to the equation:

-(-8t-20)



We get rid of parentheses

8t+8t+20+20=0

We add all the numbers together, and all the variables

16t+40=0

We move all terms containing t to the left, all other terms to the right

16t=-40

t=-40/16

t=-2+1/2

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