4(2t-1)-9=4(t+3)-1

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Solution for 4(2t-1)-9=4(t+3)-1 equation: 



4(2t-1)-9=4(t+3)-1

We move all terms to the left:

4(2t-1)-9-(4(t+3)-1)=0

We multiply parentheses

8t-(4(t+3)-1)-4-9=0



We calculate terms in parentheses: -(4(t+3)-1), so:

4(t+3)-1

We multiply parentheses

4t+12-1

We add all the numbers together, and all the variables

4t+11

Back to the equation:

-(4t+11)



We add all the numbers together, and all the variables

8t-(4t+11)-13=0

We get rid of parentheses

8t-4t-11-13=0

We add all the numbers together, and all the variables

4t-24=0

We move all terms containing t to the left, all other terms to the right

4t=24

t=24/4

t=6

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