4(2t-4)-4t=32

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Solution for 4(2t-4)-4t=32 equation: 



4(2t-4)-4t=32

We move all terms to the left:

4(2t-4)-4t-(32)=0

We add all the numbers together, and all the variables

-4t+4(2t-4)-32=0

We multiply parentheses

-4t+8t-16-32=0

We add all the numbers together, and all the variables

4t-48=0

We move all terms containing t to the left, all other terms to the right

4t=48

t=48/4

t=12

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