4(2v+11)=4(1+9v)+12

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Solution for 4(2v+11)=4(1+9v)+12 equation: 



4(2v+11)=4(1+9v)+12

We move all terms to the left:

4(2v+11)-(4(1+9v)+12)=0

We add all the numbers together, and all the variables

4(2v+11)-(4(9v+1)+12)=0

We multiply parentheses

8v-(4(9v+1)+12)+44=0



We calculate terms in parentheses: -(4(9v+1)+12), so:

4(9v+1)+12

We multiply parentheses

36v+4+12

We add all the numbers together, and all the variables

36v+16

Back to the equation:

-(36v+16)



We get rid of parentheses

8v-36v-16+44=0

We add all the numbers together, and all the variables

-28v+28=0

We move all terms containing v to the left, all other terms to the right

-28v=-28

v=-28/-28

v=1

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