4(2v+2)=2v-40

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Solution for 4(2v+2)=2v-40 equation: 



4(2v+2)=2v-40

We move all terms to the left:

4(2v+2)-(2v-40)=0

We multiply parentheses

8v-(2v-40)+8=0

We get rid of parentheses

8v-2v+40+8=0

We add all the numbers together, and all the variables

6v+48=0

We move all terms containing v to the left, all other terms to the right

6v=-48

v=-48/6

v=-8

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