4(2v-2)+7v+5=5(v-2)+3

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Solution for 4(2v-2)+7v+5=5(v-2)+3 equation: 



4(2v-2)+7v+5=5(v-2)+3

We move all terms to the left:

4(2v-2)+7v+5-(5(v-2)+3)=0

We add all the numbers together, and all the variables

7v+4(2v-2)-(5(v-2)+3)+5=0

We multiply parentheses

7v+8v-(5(v-2)+3)-8+5=0



We calculate terms in parentheses: -(5(v-2)+3), so:

5(v-2)+3

We multiply parentheses

5v-10+3

We add all the numbers together, and all the variables

5v-7

Back to the equation:

-(5v-7)



We add all the numbers together, and all the variables

15v-(5v-7)-3=0

We get rid of parentheses

15v-5v+7-3=0

We add all the numbers together, and all the variables

10v+4=0

We move all terms containing v to the left, all other terms to the right

10v=-4

v=-4/10

v=-2/5

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