4(2v-2)+v=-53

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Solution for 4(2v-2)+v=-53 equation: 



4(2v-2)+v=-53

We move all terms to the left:

4(2v-2)+v-(-53)=0

We add all the numbers together, and all the variables

v+4(2v-2)+53=0

We multiply parentheses

v+8v-8+53=0

We add all the numbers together, and all the variables

9v+45=0

We move all terms containing v to the left, all other terms to the right

9v=-45

v=-45/9

v=-5

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