4(2v-6+v)=12

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Solution for 4(2v-6+v)=12 equation: 



4(2v-6+v)=12

We move all terms to the left:

4(2v-6+v)-(12)=0

We add all the numbers together, and all the variables

4(3v-6)-12=0

We multiply parentheses

12v-24-12=0

We add all the numbers together, and all the variables

12v-36=0

We move all terms containing v to the left, all other terms to the right

12v=36

v=36/12

v=3

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