4(2w+3)=-3(w-1)+31

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Solution for 4(2w+3)=-3(w-1)+31 equation: 



4(2w+3)=-3(w-1)+31

We move all terms to the left:

4(2w+3)-(-3(w-1)+31)=0

We multiply parentheses

8w-(-3(w-1)+31)+12=0



We calculate terms in parentheses: -(-3(w-1)+31), so:

-3(w-1)+31

We multiply parentheses

-3w+3+31

We add all the numbers together, and all the variables

-3w+34

Back to the equation:

-(-3w+34)



We get rid of parentheses

8w+3w-34+12=0

We add all the numbers together, and all the variables

11w-22=0

We move all terms containing w to the left, all other terms to the right

11w=22

w=22/11

w=2

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