4(2x+0)=5(x+5)+2

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Solution for 4(2x+0)=5(x+5)+2 equation: 



4(2x+0)=5(x+5)+2

We move all terms to the left:

4(2x+0)-(5(x+5)+2)=0

We add all the numbers together, and all the variables

4(+2x)-(5(x+5)+2)=0

We multiply parentheses

8x-(5(x+5)+2)=0



We calculate terms in parentheses: -(5(x+5)+2), so:

5(x+5)+2

We multiply parentheses

5x+25+2

We add all the numbers together, and all the variables

5x+27

Back to the equation:

-(5x+27)



We get rid of parentheses

8x-5x-27=0

We add all the numbers together, and all the variables

3x-27=0

We move all terms containing x to the left, all other terms to the right

3x=27

x=27/3

x=9

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