4(2x+1)+6=-8+5(3x-2)

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Solution for 4(2x+1)+6=-8+5(3x-2) equation: 



4(2x+1)+6=-8+5(3x-2)

We move all terms to the left:

4(2x+1)+6-(-8+5(3x-2))=0

We multiply parentheses

8x-(-8+5(3x-2))+4+6=0



We calculate terms in parentheses: -(-8+5(3x-2)), so:

-8+5(3x-2)

determiningTheFunctionDomain
5(3x-2)-8

We multiply parentheses

15x-10-8

We add all the numbers together, and all the variables

15x-18

Back to the equation:

-(15x-18)



We add all the numbers together, and all the variables

8x-(15x-18)+10=0

We get rid of parentheses

8x-15x+18+10=0

We add all the numbers together, and all the variables

-7x+28=0

We move all terms containing x to the left, all other terms to the right

-7x=-28

x=-28/-7

x=+4

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