4(2x+1)+8=6(x+2)+2x

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Solution for 4(2x+1)+8=6(x+2)+2x equation: 



4(2x+1)+8=6(x+2)+2x

We move all terms to the left:

4(2x+1)+8-(6(x+2)+2x)=0

We multiply parentheses

8x-(6(x+2)+2x)+4+8=0



We calculate terms in parentheses: -(6(x+2)+2x), so:

6(x+2)+2x

We add all the numbers together, and all the variables

2x+6(x+2)

We multiply parentheses

2x+6x+12

We add all the numbers together, and all the variables

8x+12

Back to the equation:

-(8x+12)



We add all the numbers together, and all the variables

8x-(8x+12)+12=0

We get rid of parentheses

8x-8x-12+12=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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