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4(2x+1)-(x+5)=2(13-x)
We move all terms to the left:
4(2x+1)-(x+5)-(2(13-x))=0
We add all the numbers together, and all the variables
4(2x+1)-(x+5)-(2(-1x+13))=0
We multiply parentheses
8x-(x+5)-(2(-1x+13))+4=0
We get rid of parentheses
8x-x-(2(-1x+13))-5+4=0
We calculate terms in parentheses: -(2(-1x+13)), so:We add all the numbers together, and all the variables
2(-1x+13)
We multiply parentheses
-2x+26
Back to the equation:
-(-2x+26)
7x-(-2x+26)-1=0
We get rid of parentheses
7x+2x-26-1=0
We add all the numbers together, and all the variables
9x-27=0
We move all terms containing x to the left, all other terms to the right
9x=27
x=27/9
x=3
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