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4(2x+1)-2=3(2x+2)-4
We move all terms to the left:
4(2x+1)-2-(3(2x+2)-4)=0
We multiply parentheses
8x-(3(2x+2)-4)+4-2=0
We calculate terms in parentheses: -(3(2x+2)-4), so:We add all the numbers together, and all the variables
3(2x+2)-4
We multiply parentheses
6x+6-4
We add all the numbers together, and all the variables
6x+2
Back to the equation:
-(6x+2)
8x-(6x+2)+2=0
We get rid of parentheses
8x-6x-2+2=0
We add all the numbers together, and all the variables
2x=0
x=0/2
x=0
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