4(2x+1)-2x=8+4(x+5)

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Solution for 4(2x+1)-2x=8+4(x+5) equation: 



4(2x+1)-2x=8+4(x+5)

We move all terms to the left:

4(2x+1)-2x-(8+4(x+5))=0

We add all the numbers together, and all the variables

-2x+4(2x+1)-(8+4(x+5))=0

We multiply parentheses

-2x+8x-(8+4(x+5))+4=0



We calculate terms in parentheses: -(8+4(x+5)), so:

8+4(x+5)

determiningTheFunctionDomain
4(x+5)+8

We multiply parentheses

4x+20+8

We add all the numbers together, and all the variables

4x+28

Back to the equation:

-(4x+28)



We add all the numbers together, and all the variables

6x-(4x+28)+4=0

We get rid of parentheses

6x-4x-28+4=0

We add all the numbers together, and all the variables

2x-24=0

We move all terms containing x to the left, all other terms to the right

2x=24

x=24/2

x=12

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