4(2x+1)=3x-2(x-2)

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Solution for 4(2x+1)=3x-2(x-2) equation: 



4(2x+1)=3x-2(x-2)

We move all terms to the left:

4(2x+1)-(3x-2(x-2))=0

We multiply parentheses

8x-(3x-2(x-2))+4=0



We calculate terms in parentheses: -(3x-2(x-2)), so:

3x-2(x-2)

We multiply parentheses

3x-2x+4

We add all the numbers together, and all the variables

x+4

Back to the equation:

-(x+4)



We get rid of parentheses

8x-x-4+4=0

We add all the numbers together, and all the variables

7x=0

x=0/7

x=0

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