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4(2x+1)=5(x+2)
We move all terms to the left:
4(2x+1)-(5(x+2))=0
We multiply parentheses
8x-(5(x+2))+4=0
We calculate terms in parentheses: -(5(x+2)), so:We get rid of parentheses
5(x+2)
We multiply parentheses
5x+10
Back to the equation:
-(5x+10)
8x-5x-10+4=0
We add all the numbers together, and all the variables
3x-6=0
We move all terms containing x to the left, all other terms to the right
3x=6
x=6/3
x=2
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