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4(2x+1)=5(x-1)
We move all terms to the left:
4(2x+1)-(5(x-1))=0
We multiply parentheses
8x-(5(x-1))+4=0
We calculate terms in parentheses: -(5(x-1)), so:We get rid of parentheses
5(x-1)
We multiply parentheses
5x-5
Back to the equation:
-(5x-5)
8x-5x+5+4=0
We add all the numbers together, and all the variables
3x+9=0
We move all terms containing x to the left, all other terms to the right
3x=-9
x=-9/3
x=-3
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